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10x^2-46x-20=0
a = 10; b = -46; c = -20;
Δ = b2-4ac
Δ = -462-4·10·(-20)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2916}=54$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-54}{2*10}=\frac{-8}{20} =-2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+54}{2*10}=\frac{100}{20} =5 $
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